H=2t^2+2t+40

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Solution for H=2t^2+2t+40 equation: 



=2H^2+2H+40

We move all terms to the left:

-(2H^2+2H+40)=0

We get rid of parentheses

-2H^2-2H-40=0

a = -2; b = -2; c = -40;
Δ = b2-4ac
Δ = -22-4·(-2)·(-40)
Δ = -316
Delta is less than zero, so there is no solution for the equation

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